In a series LCR circuit the voltage across the resistance, capacitance and inductance is 10V each. If the capacitance is short circuited , the voltage across the inductance will be
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a
10V
b
10 V/2
c
(10/3)V
d
20V
answer is B.
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Detailed Solution
Here R=XL=XC (∵ voltage across them is same) Total voltage in the circuit,V=I[R2+(XL−XC)2]1/2 =IR=10V When capacitor is short circuitedI=10(R2+XL2)1/2=102R Potential drop across inductanceIXL=IR=10V/2