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Q.

In series LCR circuit voltage drop across resistance is 8 V across inductor is 6 V and across capacitor is 12 V. Then

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a

voltage of the source will be leading current in the circuit

b

voltage drop across each element will be less than the applied voltage

c

power factor of circuit will be 4/3

d

none of these

answer is D.

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Detailed Solution

Since cosϕ=RZ=IRIZ=810=45(Also cos ϕ can never be greater than 1)Hence, (c) is wrong.Also, IXC>IXL⇒XC>XL∴Current will be leadingIn an LCR circuit,V=vL-vC2+vR2=6-122+82V = l0; which is less than voltage drop across capacitor.
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