In series LCR circuit voltage drop across resistance is 8V, across inductor is 6V and across capacitor is 12V. then

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Voltage of the source will be leading current in the circuit

Voltage drop across each element will be less than the applied voltage

Power factor of circuit will be 4/3

None of these

answer is D.

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Detailed Solution

Since cosθ=RZ=IRIZ=810=45 (also, cosθ can never be greater than 1)Hence (c) is wrong.Also IXC>IXL⇒XC>XL Current will be leading.In an LCR circuit,v=(vL−vC)2+vR2=(6−12)2+82 V=10; which is less than voltage drop across capacitor.

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