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AC Circuits

Question

In a series L-R circuit, connected with a sinusoidal ac source, the maximum potential difference across L and R are 3 volts and 4 volts respectively.

Moderate
Question

At an instant the potential difference across resistor is 2 volts. The potential difference in volt, across the inductor at the same instant will be :

Solution

In LR CIRCUIT 

tan ϕ=VLVR=IRMS ωLIRMS R=34  As per the given data

VLVR=34=VL`2 new value of vL=3 COS 600=1.5 VOLT

Question

At the same instant, the magnitude of potential difference in volt, across the source may be

Solution

V=V2L+V2R=22+1.52=2.5  volt



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Similar Questions

In the circuit shown in figure, R is a pure resistor, L is an inductor of negligible resistance (as compared to R), S is a 100 V 50 Hz ac source of negligible resistance. With either key K1 alone or K2 alone closed, the current is I0. If the source is changed to 100 V, 100 Hz the current with K1 alone closed and with K2 alone closed will be, respectively,


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