In a series L-R circuit, connected with a sinusoidal ac source, the maximum potential difference across L and R are 3 volts and 4 volts respectively.At an instant the potential difference across resistor is 2 volts. The potential difference in volt, across the inductor at the same instant will be :At the same instant, the magnitude of potential difference in volt, across the source may be

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Detailed Solution

In LR CIRCUIT tan ϕ=VLVR=IRMS ωLIRMS R=34 As per the given dataVLVR=34=VL`2 new value of vL=3 COS 600=1.5 VOLTV=V2L+V2R=22+1.52=2.5 volt

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