Question

In a series L-R circuit, connected with a sinusoidal ac source, the maximum potential difference across L and R are 3 volts and 4 volts respectively.

Moderate

Question

At an instant the potential difference across resistor is 2 volts. The potential difference in volt, across the inductor at the same instant will be :

Solution

In LR CIRCUIT

tan $\varphi $=$\frac{{V}_{L}}{{V}_{R}}$=$\frac{{I}_{RMS}\omega L}{{I}_{RMS}R}$=$\frac{3}{4}$ As per the given data

$\frac{{V}_{L}}{{V}_{R}}=\frac{3}{4}=\frac{{{V}_{L}}^{`}}{2}\phantom{\rule{0ex}{0ex}}newvalueof{v}_{L}=3COS{60}^{0}=1.5VOLT$

Question

At the same instant, the magnitude of potential difference in volt, across the source may be

Solution

V=$\sqrt{{{V}^{2}}_{L}+{{V}^{2}}_{R}}=\sqrt{{2}^{2}+1.{5}^{2}}=2.5volt$

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Similar Questions

In the circuit shown in figure, R is a pure resistor, L is an inductor of negligible resistance (as compared to R), S is a 100 V 50 Hz ac source of negligible resistance. With either key K_{1} alone or K_{2} alone closed, the current is *I _{0}*. If the source is changed to 100 V, 100 Hz the current with K

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