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Q.

Several  spherical drops of a liquid of density ‘d’ and radius ‘r’ coalesce to form a single drop of radius ‘R’. If all the energy released is converted into K.E. Then the velocity acquired by the drop is ( T is the surface tension of the liquid )

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a

6Td1r−1R

b

3Td1r−1R

c

T6d1r−1R

d

T3d1r−1R

answer is A.

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Detailed Solution

12mv2=(4πr2n-4πR2)Tv2=8πT(r2n4π3r3nvd-R24π3R3d) ⇒v =[ 6Td(1r-1R)]12
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