Q.
A shaft rotating at 3000 rpm is transmitting a power of 3.14 KW. The magnitude of the driving torque is ………. Nm
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a
6
b
10
c
15
d
22
answer is B.
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Detailed Solution
Power = torque x angular velocity3.14 x 103 = τ X 2X3.14X300060 SO τ = 10 Nm
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