Question

A shaft rotating at 3000 rpm is transmitting a power of 3.14 KW. The magnitude of the driving torque is ………. Nm

Moderate

Solution

Power = torque x angular velocity
3.14 x 10³ = $τ$ X 2X3.14X $\frac{3000}{60}$
SO $τ = 10 N m$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

SCAN ME