Shape of string transmitting wave along $$x-axis$$ at some instant is shown. Velocity of point P is $$v=4$$π $$cm/s$$ and θ$$=$$$$tan$$−$$10.004$$π

Question

Shape of string transmitting wave along $$x-axis$$ at some instant is shown. Velocity of point P is  $$v=4$$π $$cm/s$$ and  θ$$=$$$$tan$$−$$10.004$$π

Infinity Learn · Accepted Answer

Wave length of the wave, λ$$=1m$$  maximum particle velocity, $$Vmax=A$$ω$$=4$$π ∴wave velocity, $$v=$$∂$$y/$$∂t∂$$y/$$∂$$x=4$$π×$$10$$−$$2tan$$θ$$=4$$π×$$10$$−$$24$$π×$$10$$−$$3=10m/s$$ ∵wave $$velocity=particle$$ velocityslope of the wave also frequency, f or  ϑ$$=V$$λ$$=V1=10HzVmax=A$$ω$$4$$π×$$10$$−$$2=A2$$π$$(10)Amplitude$$ of the $$waveA=2$$×$$10$$−$$3m$$   and maximum accelertion of the particle $$amax=A$$ω$$2=80$$$$π$$$$2cm/sec2$$

Shape of string transmitting wave along x-axis at some instant is shown. Velocity of point P is $v = 4 π$ cm/s and $θ = \tan^{- 1} (0.004 π)$

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Shape of string transmitting wave along x-axis at some instant is shown. Velocity of point P is v=4π cm/s and θ=tan−10.004π

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Shape of string transmitting wave along x-axis at some instant is shown. Velocity of point P is $v = 4 π$ cm/s and $θ = \tan^{- 1} (0.004 π)$