Questions
A sheet ABCD in the shape of a Rhombus has mass m and length of each side as shown in figure. Then moment of inertia of the sheet about side AB is
detailed solution
Correct option is B
M.I. of ABCD about AB=M.I. of the rectangle CDEF about EF + M.I. of the triangle ADE about AE - M.I. of triangle BCF about BF =M.I. of rectangle CDEF about EF DE=AD sin600=3 l2 ∴ I=13mDE2 = 13m3 l22=14ml2Talk to our academic expert!
Similar Questions
The moment of inertia of a circular disc of radius 2 m and mass 2 kg, about an axis passing through its centre of mass is 2 kg – . Its moment of inertia about an axis parallel to this axis and passing through its edge (in Kg -) is
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