A shell is fired from a cannon with a velocity v at an angle θ with the horizontal direction At the highest point in its path, it explodes into two pieces of equal masses. One of the pieces retraces its path to the cannon. The speed of the other piece immediately after the explosion is
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a
3vcosθ
b
2vcosθ
c
(3/2) vcosθ
d
Vcosθ
answer is A.
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Detailed Solution
Applying the law of conservation of momentum, we have(2m)(vcosθ)=−m(vcosθ)+mv2 2vcosθ+vcosθ=v2 v2=3vcosθ