A shell is fired from a gun from the bottom of a hill along its slope. The slope of the hill is α = 30°, the angle of the barrel to the horizontal β = 60°. The initial velocity v of the shell is 21 m/s. Then, the distance of point from the gun at which shell falls is
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a
10 m
b
20 m
c
30 m
d
40 m
answer is C.
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Detailed Solution
Here, u = 21 m/s, α=30∘,θ=(β−α)=60∘−30∘=30∘Maximum rangeR=2u2gsinθcos(θ+α)cos2α=2×(21)2×sin30∘cos60∘9.8×cos230∘=30m