First slide

Second law

Question

A shell of mass 0.01 kg fired by a gun of mass 10 kg. If the muzzle speed of the shell is 50 ms^–1, what is the recoil speed of the gun?

Moderate

A

0.01 m/s
B

0.02 m/s
C

0.03 m/s
D

0.05 m/s

Solution

If v be the recoil speed of the gun and u be the muzzle speed of the shell, then as momentum of the system is conserved, we can write Mv + m(v - u) = 0 ⇒ V = mu/(M + m).
$\therefore$ V = 0.01 x 50 / (10 + 0.01) = 0.05m/s

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