Questions
A shell of mass 2 m fired with speed u at an angle to the horizontal explodes at the highest point of its motion into two fragments of mass m each. If one fragment, whose initial speed is zero, falls vertically, .the distance at which the other fragment falls from the gun is given by
detailed solution
Correct option is A
Momentum of the shell at highest point=2m(ucosθ)As one fragment has initial speed zero (stationary) and hence the other fragment of mass m has velocity component (2ucosθ) in horizontal direction. This will move under gravity. So it wilt fall at a distance which is equal to range.R=u2sin2θgHence, distance covered from the gun=R2+R=32R=32u2sin2θgSimilar Questions
Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.
Reason : Range of projectile does not depend on the initial velocity of a body.
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