A shell of mass $$2$$ m fired with speed u at an angle θ to the horizontal explodes at the highest point of its motion into two fragments of mass m each. If one fragment, whose initial speed is zero, falls vertically, .the distance at which the other fragment falls from the gun is given by

Question

A shell of mass $$2$$ m fired with speed u at an angle θ to the horizontal explodes at the highest point of its motion into two fragments of mass m each. If one fragment, whose initial speed is zero, falls vertically, .the distance at which the other fragment falls from the gun is given by

Infinity Learn · Accepted Answer

Momentum of the shell at highest $$point=2m(ucos$$⁡θ$$)As$$ one fragment has initial speed zero (stationary) and hence the other fragment of mass m has velocity component (2ucos$$⁡θ$$) in horizontal direction. This will move under gravity. So it wilt fall at a distance which is equal to range.$$R=u2sin$$⁡$$2$$θgHence, distance covered from the $$gun=R2+R=32R=32u2sin$$⁡$$2$$θg

A shell of mass 2 m fired with speed u at an angle $θ$ to the horizontal explodes at the highest point of its motion into two fragments of mass m each. If one fragment, whose initial speed is zero, falls vertically, .the distance at which the other fragment falls from the gun is given by

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A shell of mass 2 m fired with speed u at an angle θ to the horizontal explodes at the highest point of its motion into two fragments of mass m each. If one fragment, whose initial speed is zero, falls vertically, .the distance at which the other fragment falls from the gun is given by

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A shell of mass 2 m fired with speed u at an angle $θ$ to the horizontal explodes at the highest point of its motion into two fragments of mass m each. If one fragment, whose initial speed is zero, falls vertically, .the distance at which the other fragment falls from the gun is given by