Questions
A ship A is moving Westwards with a speed of and a ship B 100 km South of A, is moving Northwards with a speed of 10 km . The time after which the distance between them becomes shortest, is
detailed solution
Correct option is D
Given situation is shown in the figure. Velocity of ship AvA=10 km h-1towards west Velocity of ship BvB=10 km h-1towards north OS = 100 kmOP = shortest distanceRelative velocity between A and B isvAB=vA2+vB2=102 km h-1cos45°=OPOS;12=OP100OP=1002=10022=502 kmThe time after which distance between them equals to OP is given byt=OPvAB=502102⇒t=5 hTalk to our academic expert!
Similar Questions
The moment of inertia of a circular disc of radius 2 m and mass 2 kg, about an axis passing through its centre of mass is 2 kg – . Its moment of inertia about an axis parallel to this axis and passing through its edge (in Kg -) is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests