Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A ship ,4 sailing due east with a velocity of 10 km/h happens to appear sailing due north with a velocity of 5 km/h , to a person, sitting in a moving ship B. Determine the velocity (absolute) of ship B.

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

55km/h,tan−1⁡(1/2)S of E

b

55km/h,tan−1⁡(1/2)E of S

c

45km/h,tan−1⁡(1/2)S of E

d

45km/h,tan−1⁡(1/2)E of S

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Here we are given velocity of ‘A’, v→A=10i^Velocity of 'A' w.r.t ‘B’, v→A/B=5j^Now v→A/B=v→A−v→B5j^=10i^−v→B⇒v→B=10i^−5j^Hence velocity of B,vB=102+52=55km/htan⁡θ=510=12θ=tan−1⁡12S of E
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon