A S.H.M. is represented by x=52sin2πt+cos2πt The amplitude of the S.H.M. is
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a
10 cm
b
20 cm
c
52cm
d
50 cm
answer is A.
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Detailed Solution
R=a2+b2+2abcosϕgiven displacement equation is x=52sin2πt+cos2πt The given equation can be written as x=52sin2πt+52sin2πt+π2Here ϕ=π2R=522+522+2×52×52cosπ2 R=522+522 R=10 cm