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Q.

A S.H.M. is represented by x=52sin2πt+cos2πt The amplitude of the S.H.M. is

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a

10 cm

b

20 cm

c

52cm

d

50 cm

answer is A.

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Detailed Solution

R=a2+b2+2abcosϕgiven displacement equation is  x=52sin2πt+cos2πt The given equation can be written as  x=52sin2πt+52sin2πt+π2Here  ϕ=π2R=522+522+2×52×52cosπ2 R=522+522 R=10    cm
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