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Questions  

A S.H.M. is represented by x=52(sin2πt+cos2πt). The amplitude of the S.H.M. is

a
10 cm
b
20 cm
c
52cm
d
50 cm

detailed solution

Correct option is A

x=52sin2π t+cos2π t=52sin2π t+52cos2π tx=52sin2πt+52sin 2π t+π2Phase difference between constituent waves φ=π2∴Resultant amplitude A=(52)2+(52)2=10 cm.

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