First slide

Magnetic properties of matter

Question

A short bar magnet of magnetic moment $30 {Am}^{2}$ has a cross sectional area of $1.5 \times 10^{- 4} m^{2}$ . If the intensity of magnetisation of the magnet is $10^{5} A / m$ , the length ( in m ) of the magnet is

Moderate

Solution

Intensity of magnetisation $I = \frac{M}{V} = \frac{M}{A L}$
$\begin{matrix} L = \frac{M}{A I} \\ P u t M = 30 A m^{2}, A = 1.5 \times 10^{- 4} m^{2}, I = 10^{5} A / m, L = ? \\ ∴ L = \frac{30}{1.5 \times 10^{- 4} \times 10^{5}} = 2 m \end{matrix}$

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