A short bar magnet of magnetic moment 20Am2 has a cross sectional area of 1.5×10-4m2 . If the intensity of magnetisation of the magnet is 105A/m , the length of the magnet is
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a
0.33m
b
0.13cm
c
1.33m
d
1.33cm
answer is C.
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Detailed Solution
Formula : Intensity of magnetization I=MV ⇒I=MALGiven : M=20Am2A=1.5×10-4m2l=105A/m∴I=MAl=201.5×10-4×105=43=1.33 m