A short bar magnet of magnetic moment 2Am2and moment of inertia 6×102kg/m2 is freely suspended such that the magnetic axial line is in the direction of magnetic meridian. If the magnet is displaced by very small angle ( 3o), the angular acceleration is y×10-6rad/s2 . Find y. (Magnetic induction of earth’s horizontal field = 4×10-4T)

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π20

π45

π60

π75

answer is B.

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Detailed Solution

α=MBIθ=2×4×10-4×3×π6×102×180 ⇒α=π45×10-6rad/s2

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