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Q.

A short bar magnet of magnetic moment 0.8 JT-1 is placed in a uniform magnetic field of 0.32 T . The magnet is in stable equilibrium. When the potential energy is

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a

0.256 J

b

-0.256 J

c

zero

d

-0.512 J

answer is B.

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Detailed Solution

Here magnetic moment  M=0.8 JT−1Magnetic field  B=0.32 TWhen a bar magnet is placed in a uniform magnetic field; its potential energy U=-M→. B→ ⇒U=-MBcosθFor stable equilibrium  θ=0⇒U=-MB ⇒U=-0.8×0.32 ⇒U=-0.256 J .
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