A short bar magnet of magnetic moment 0.8 JT-1 is placed in a uniform magnetic field of 0.32 T . The magnet is in stable equilibrium. When the potential energy is
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a
0.256 J
b
-0.256 J
c
zero
d
-0.512 J
answer is B.
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Detailed Solution
Here magnetic moment M=0.8 JT−1Magnetic field B=0.32 TWhen a bar magnet is placed in a uniform magnetic field; its potential energy U=-M→. B→ ⇒U=-MBcosθFor stable equilibrium θ=0⇒U=-MB ⇒U=-0.8×0.32 ⇒U=-0.256 J .