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A short bar magnet of magnetic moment $20 A m^{2}$ has cross sectional area of $1.5 \times 10^{- 4} m^{2}$ . If the intensity of magnetization of the magnet is $10^{5}$ A/m. The length of magnet is

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0.33 m

0.13 cm

1.33 m

1.33 cm

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detailed solution

Correct option is C

I=MV=MA×2l2l=MIA=20105×1.5×10−4=1.33 m

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A short bar magnet of magnetic moment 20Am2 has cross sectional area of 1.5 × 10-4m2. If the intensity of magnetization of the magnet is 105A/m. The length of magnet is

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A short bar magnet of magnetic moment $20 A m^{2}$ has cross sectional area of $1.5 \times 10^{- 4} m^{2}$ . If the intensity of magnetization of the magnet is $10^{5}$ A/m. The length of magnet is