A Short bar magnet is placed in the magnetic meridian of the earth with north pole pointing north. Neutral points are found at a distance of 30cm from the magnet an the east west line drawn through the middle point of the magnet. The magnetic moment of the magnet in Am2 is BH=3.6×10-5T
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a
9.72
b
4.9
c
19.4
d
14.6
answer is A.
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Detailed Solution
When North pole of a bar magnet facing North Null points are obtained an equatorial linehere B=BH BH=μ04πMd3Given BH=3.6×10-5T d=30 cm3.6×10-5 = 10-7×M(0.3)3M = 3.6×10-5×27×10-310-7=9.72 A m2