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Q.

A Short bar magnet is placed in the magnetic meridian of the earth with north pole pointing north. Neutral points are found at a distance of 30cm from the magnet an the east west line drawn through the middle point of the magnet. The magnetic moment of the magnet in  Am2 is BH=3.6×10-5T

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a

9.72

b

4.9

c

19.4

d

14.6

answer is A.

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Detailed Solution

When North pole of a bar magnet facing  North Null points are obtained an equatorial linehere  B=BH                                         BH=μ04πMd3Given  BH=3.6×10-5T          d=30 cm3.6×10-5 = 10-7×M(0.3)3M = 3.6×10-5×27×10-310-7=9.72 A m2
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