A Short bar magnet is placed in the magnetic meridian of the earth with north pole pointing north. Neutral points are found at a distance of $$30cm$$ from the magnet an the east west line drawn through the middle point of the magnet. The magnetic moment of the magnet in $$Am2$$ is $$BH=3.6$$×$$10-5T$$

Question

A Short bar magnet is placed in the magnetic meridian of the earth with north pole pointing north. Neutral points are found at a distance of $$30cm$$ from the magnet an the east west line drawn through the middle point of the magnet. The magnetic moment of the magnet in  $$Am2$$ is $$BH=3.6$$×$$10-5T$$

Infinity Learn · Accepted Answer

When North pole of a bar magnet facing  North Null points are obtained an equatorial linehere  $$B=BH$$                                         $$BH=$$μ$$04$$$$π$$$$Md3Given$$  $$BH=3.6$$×$$10-5T$$          $$d=30$$ $$cm3.6$$×$$10-5$$ $$=$$ $$10-7$$×$$M(0.3)3M$$ $$=$$ $$3.6$$×$$10-5$$×$$27$$×$$10-310-7=9.72$$ A $$m2$$

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A Short bar magnet is placed in the magnetic meridian of the earth with north pole pointing north. Neutral points are found at a distance of 30cm from the magnet an the east west line drawn through the middle point of the magnet. The magnetic moment of the magnet in Am2 is BH=3.6×10-5T

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