A short linear object of length l lies along the axis of a concave mirror of focal length f at a distance u from the pole of the minor. The size of the image is approximately equal to

Question

Infinity Learn · Accepted Answer

From  mirror  $$formula1f=1v+1u$$      .   .   .   .   .  iDifferentiating  equation i,  we  $$obtain0=$$−$$1v2dv$$−$$1u2du$$⇒$$dv=$$−$$vu2du$$   .   .   .   iiAlso  from  $$equationivu=fu$$−f   .   .   .   .   .   .  iiiFrom  equations  ii  and  iii  we  $$getdv=$$−fu−$$f2$$.lTherefore  size   of  image  is  fu−$$f2l$$

A short linear object of length l lies along the axis of a concave mirror of focal length f at a distance u from the pole of the minor. The size of the image is approximately equal to

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material