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A short magnet of moment 6.75 Am2 produces a neutral point on its axis. If horizontal component of earth's magnetic field is 5 x 10-5 Wb/m2, then the distance of the neutral point should be

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a

10 cm

b

20 cm

c

30 cm

d

40cm

answer is C.

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Detailed Solution

At neutral point, Magnetic field due to magnet=Magnetic field due to earthμ04π2Md3=5 x 10-5⇒10-7 x 2 x 6.75d3=5 x 10-5⇒d=0.3m=30cm

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