First slide

Earth's Magnetism

Question

A short magnet of moment 6.4 A-m² lies in the magnetic meridian with north pole facing south (B_H = 1.6 gauss). The distance between the two neutral points is

Moderate

Solution

$\begin{array}{rcl} B_{a} & = & B_{H} = \frac{μ_{0}}{4 π} \frac{2 M}{d^{3}}; \\ d^{3} & = & \frac{10^{- 7} x 2 x 6.4}{1.6 x 10^{- 4}} \end{array}$
d = 0.2 m , 2d = 0.4 m = 40 cm along axial line

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