A short magnet of moment 6.4 A-m2 lies in the magnetic meridian with north pole facing south (BH = 1.6 gauss). The distance between the two neutral points is

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answer is 3.

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Detailed Solution

Ba=BH=μ04π2Md3 ; d3=10-7 x 2 x 6.41.6 x 10-4d = 0.2 m , 2d = 0.4 m = 40 cm along axial line

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