A short magnet oscillates in vibration magneto mater with a frequency 10 Hz where horizontal component of earth’s magnetic field is 12 μT. A downward current of 15 A is established in the vertical wire of infinite length placed 20 cm west of the magnet. Then the new frequency is

Question

A  short magnet oscillates in vibration magneto mater with a frequency 10  Hz      where  horizontal component of earth’s magnetic field is 12 μT.      A downward  current of 15 A is established in the vertical wire of infinite length placed  20 cm west of the magnet. Then the new frequency is

Infinity Learn · Accepted Answer

From n=12πMBI     As nαB       	n1n2=Β1B2      B1=BH=12  μT      B2=      resultant of  B and BH      , Where B=μ0i2π d     	B=2×10−7×1520×10−2     	B=15  μT     B2=15−12=3  μT      ∴  10n2=123  ⇒  n2=5  Hz

A short magnet oscillates in vibration magneto mater with a frequency $10 H z$ where horizontal component of earth’s magnetic field is 12 $μ T .$ A downward current of 15 A is established in the vertical wire of infinite length placed 20 cm west of the magnet. Then the new frequency is

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