A short-circuited coil is placed in a time-varying magnetic field. Electrical power is dissipated due to the current induced in the coil. If the number of tums were to be quadrupled and the wire radius halved, the electric power dissipated would be

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halved

the same

doubled

quadrupled

answer is B.

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Detailed Solution

Here N2=4N1 so e2=4e1 New length l2=4l1Because the radius of the wire is halved and hence the area becomes one-fourth, i.e.,A2=A14 or R2=16R1∴ Power P2=e22R2=4e1216R1=e12R1=P1

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