First slide
Faraday's law of Electromagnetic induction
Question

A short-circuited coil is placed in a time-varying magnetic field. Electrical power is dissipated due to the current induced in the coil. If the number of tums were to be quadrupled and the wire radius halved, the electric power dissipated would be

Easy
Solution

 Here N2=4N1 so e2=4e1  New length l2=4l1
Because the radius of the wire is halved and hence the area becomes one-fourth, i.e.,
A2=A14 or R2=16R1 Power P2=e22R2=4e1216R1=e12R1=P1

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