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A short-circuited coil is placed in a time-varying magnetic field. Electrical power is dissipated due to the current induced in the coil. If the number of turns were to be
quadrupled and the wire radius halved, the electrical power dissipated would be,

a
halved
b
the same
c
doubled
d
quadrupled

detailed solution

Correct option is B

Power P=ε2R hence ε=−dφdt where φ=NBA∴ ε=−NAdBdt Also R∝lr2∝Nr2 where R= resistance, r= radius, l= length ∴ P∝N2r2N∝Nr2N becomes quadrupled and radius is halved.⇒P1P2=1

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