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Q.

A short-circuited coil is placed in a time-varying magnetic field. Electrical power is dissipated due to the current induced in the coil. If the number of turns were to bequadrupled and the wire radius halved, the electrical power dissipated would be,

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a

halved

b

the same

c

doubled

d

quadrupled

answer is B.

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Detailed Solution

Power P=ε2R hence ε=−dφdt where φ=NBA∴ ε=−NAdBdt Also R∝lr2∝Nr2 where R= resistance, r= radius, l= length ∴ P∝N2r2N∝Nr2N becomes quadrupled and radius is halved.⇒P1P2=1
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