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Q.

The shortest wavelength in the Lyman series of hydrogen spectrum is 912 Ao corresponding to a photon energy of 13.6 eV. The shortest wavelength in the Balmer series is about

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a

3648 Ao

b

8208 Ao

c

1228 Ao

d

6566 Ao

answer is A.

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Detailed Solution

In Lyman series λminL=1R and λminB=4R ⇒λminB=4×λminL=4×912=3648 Ao
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