The shortest wavelength in the Lyman series of hydrogen spectrum is 912 A0 . The shortest wavelength in the Balmer series in hydrogen spectrum is about
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a
3648 A0
b
8208 A0
c
1228 A0
d
6566 A0
answer is A.
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Detailed Solution
In Lyman series λminL=1RandλminB=4R⇒λminB=4×λminL=4×912=3648A0