First slide

Projection Under uniform Acceleration

Question

A shot is fired from a point at a distance of 200 m from the foot of a tower 100 m high so that it just passes over it horizontally. The direction of shot with horizontal is

Moderate

A

30°
B

45°
C

60°
D

70°

Solution

$H = 100 m, R = 2 \times 200 = 400 m \tan θ = \frac{4 H}{R} \Rightarrow \tan θ = \frac{4 \times 100}{400} = 1 θ = 45^{\circ} [∵ \frac{H}{R} = \frac{\tan θ}{4}]$

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