Show that the vector A=i^-j^+2k^ is parallel to a vector B=3i^-3i^+6k^
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a
A=-13B
b
A=-B
c
A=13B
d
None of these
answer is C.
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Detailed Solution
A vector A is parallel to an another vector B if it can be written asA=m BA=(i^-j^+2k^)=13(3i^-3j^+6k^)A=13BThis implies that A is parallel to B and magnitude of A is 13 times the magnitude of B.