As shown in the above graph, a monoatomic ideal gas whose initial temperature is T0 at the point A is taken to the final state at point C via point B. Now, choose the correct statement:

Work done = Area of ABC with respect to volume axis i.e V-axis= area under AB = area under BC=P02V0−V0+0=P0V0=nRT0=RT0(∵n=1, one mole given )where R is gas constant.Change in internal energy=ΔU=nCνΔT where Cv is specific heat capacity at constant volume and is equal to 32R for monoatomic gas=1×32R×4T0−T0=92RT0(at C, Temperature T = 4T0 due to 2Po×2Vo=nRT and PoVo = nR0)∴ Heat absorbed=ΔU+ΔW=92RT0+RT0=112RT0Hence, only option 1 is correct.