As shown in the below figure a body is projected down the plane, then time of flight is
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a
T=2usin (α+β)g cos β
b
T=2usin (α−β)g cos β
c
T=2ucos (α−β)g cos β
d
T=2ucos (α−β)sin β
answer is A.
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Detailed Solution
time of flight=T=2usinθa Here angle of projection with respect to inclined plane= θ=α+β acceleration =a=gcosβ substitute ∴time of flight=T=2usinα+βgcosβ