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Q.

As shown in the below figure a body is projected up the plane, then the time of flight and maximum range when β=0 are

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a

T=2u sin αg,  Rmax=u2g

b

T=2u cos α3g,  Rmax=ug

c

T=2u tan αg,  Rmax=2ug2

d

T=2u tan αg,  Rmax=u2g

answer is A.

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Detailed Solution

time of flight =T=2usinα−βgcosβ ⇒T=2usinαg∵β=0 maximum range=Rmax=u2sin2θg ⇒Rmax=u2g         sin2θ=1  for  maximum
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