As shown in the below figure a body is projected up the plane, then the time of flight and maximum range when β=0 are

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T=2u sin αg, Rmax=u2g

T=2u cos α3g, Rmax=ug

T=2u tan αg, Rmax=2ug2

T=2u tan αg, Rmax=u2g

answer is A.

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Detailed Solution

time of flight =T=2usinα−βgcosβ ⇒T=2usinαg∵β=0 maximum range=Rmax=u2sin2θg ⇒Rmax=u2g sin2θ=1 for maximum

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