As shown in fig. (10), P and Q are two coaxial
conducting loops separated by some distance. When the switch S is closed, a clockwise current I_pflows in P (as seen by E) and an induced current $I_{Q_{1}}$ , flows in Q. The switch remains closed for a long time. when S is opened, a current $I_{Q_{2}}$ flows in Q. Then the directions of $I_{Q_{1}} and I_{Q_{2}}$ (as seen by E) are:

Question

As shown in fig. (10), P and Q are two coaxial

conducting loops separated by some distance. When the switch S is closed, a clockwise current I_pflows in P (as seen by E) and an induced current $I_{Q_{1}}$ , flows in Q. The switch remains closed for a long time. when S is opened, a current $I_{Q_{2}}$ flows in Q. Then the directions of $I_{Q_{1}} and I_{Q_{2}}$ (as seen by E) are:

Infinity Learn · Accepted Answer

Due to $$IQ1$$, B will be towards E. So, $$IQ1$$ will be anticlockwise. Dup to $$IQ2$$, B will be away from E So, $$IQ2will$$ be clockwise.

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