As shown in fig. when a spherical cavity (centered at O) of radius 1 is cut out of a uniform sphere of radius R (centered at C), the center of mass of remaining (shaded) part of sphere is at G, i.e. on the surface of the cavity. R can be determined by the equation :
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a
R2+R−12−R=1
b
R2+R+12−R=1
c
R2−R+12−R=1
d
R2−R−12−R=1
answer is B.
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Detailed Solution
Moment of masses about COM is zero.∴Mremaining×GC = Mcavity×OC⇒Mtotal− Mcavity×GP−CP = Mcavity×CP−OPSince, Mass∝radius3⇒R3−132−R=13R−1 ⇒R2+R+12−R=1