Questions
As shown in fig. when a spherical cavity (centered at O) of radius 1 is cut out of a uniform sphere of radius R (centered at C), the center of mass of remaining (shaded) part of sphere is at G, i.e. on the surface of the cavity. R can be determined by the equation :
detailed solution
Correct option is B
Moment of masses about COM is zero.∴Mremaining×GC = Mcavity×OC⇒Mtotal− Mcavity×GP−CP = Mcavity×CP−OPSince, Mass∝radius3⇒R3−132−R=13R−1 ⇒R2+R+12−R=1Talk to our academic expert!
Similar Questions
The disc of mass M and radius R with uniform surface mass density as shown in the figure. The centre of mass of quarter disc (the shaded area) is at the position where x is _____, (Round off to the Nearest integer)
[a is the shaded area as shown in the figure]
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