As shown in the figure, a bob of mass m is tied by a massless string whose other end portion is wound on a fly wheel (disc) of radius r and mass m. when released from rest the bob starts falling vertically. When it has covered a distance of h, the angular speed of the wheel will be

Question

Infinity Learn · Accepted Answer

Loss in potential energy is gain in translational bob and rotational disc kinetic energy.⇒$$mgh$$$$=12mv2+12l$$ω$$2$$                     here,    $$v=$$ωr no slipping⇒$$mgh$$$$=12m$$ω$$2r2+12mr22$$ω$$2$$    ⇒$$mgh$$$$=34m$$ω$$2r2$$    ​⇒  ω$$=4gh3r2=1r4gh3$$

As shown in the figure, a bob of mass m is tied by a massless string whose other end portion is wound on a fly wheel (disc) of radius r and mass m. when released from rest the bob starts falling vertically. When it has covered a distance of h, the angular speed of the wheel will be

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