As shown in the figure, charges +q and -q are placed at the vertices B and C of an isosceles triangle. The potential at the vertex A is
14πε0.2qa2+b2
Zero
14πε0.qa2+b2
14πε0.(−q)a2+b2
Potential at A = Potential due to (+q) charge + Potential due to (– q) charge=14πε0.qa2+b2+14πε0(−q)a2+b2=0