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Questions  

As shown in the figure, charges +q and -q are placed at the vertices B and C of an isosceles triangle. The potential at the vertex A is 

a
14πε0.2qa2+b2
b
Zero
c
14πε0.qa2+b2
d
14πε0.(−q)a2+b2

detailed solution

Correct option is B

Potential at A = Potential due to (+q) charge                        + Potential due to (– q) charge=14πε0.qa2+b2+14πε0(−q)a2+b2=0

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