As shown in the figure, charges +q and -q are placed at the vertices B and C of an isosceles triangle. The potential at the vertex A is
14πε0·2qa2+b2
Zero
14πε0·qa2+b2
14πε0·(-q)a2+b2
Potential at A = Potential due to ( +q) charge + Potential due to (-q) charge
=14πε0·qa2+b2+14πε0(-q)a2+b2=0