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Questions  

As shown in the figure, charges +q and -q are placed at the vertices B and C of an isosceles triangle. The potential at the vertex A is

a
14πε0·2qa2+b2
b
Zero
c
14πε0·qa2+b2
d
14πε0·(-q)a2+b2

detailed solution

Correct option is B

Potential at A = Potential due to ( +q) charge + Potential due to (-q) charge=14πε0·qa2+b2+14πε0(-q)a2+b2=0

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