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Q.

As shown in the figure, a light ray is incident on face AB of prism ABC. The second prism is then arranged in such a manner that emergent ray from prism ABC  is falling normally on face A'B' of prism A'B'C'. What is the net deviation produced by the optical system of the two prisms?

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a

48o

b

112o

c

32o

d

18o

answer is A.

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Detailed Solution

From prism 1 :sin⁡i=μsin⁡r⇒sin⁡53∘=43×sin⁡r⇒sin⁡r=34×45=35⇒r=37∘Total deviation = 16oon both ends = 32oIn prism 2 :δ1A1=δ2A2⇒δ2=3774×32∘=16∘ Total deviation =δ1+δ2=32 + 16 = 48o
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