As shown in the figure a metal rod makes contact and complete the circuit. The circuit is perpendicular to the magnetic field with B=0.15 tesla. If the resistance is 3 Ω, force needed to move the rod as indicated with a constant speed of 2m/sec is
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a
3.75×10−3N
b
3.75×10−2N
c
3.75×102N
d
3.75×10−4N
answer is A.
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Detailed Solution
Induced current in the circuit i=BvlRMagnetic force acting on the wire Fm=Bil=BBvlR l⇒Fm=B2vl2R External force needed to move the rod with constant velocity(Fm)=B2vl2R=(0.15)2×(2)×(0.5)23=3.75×10−3N