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Q.

As shown in the figure a metal rod makes contact and complete the circuit. The circuit is perpendicular to the magnetic field with B=0.15 tesla. If the resistance is  3 Ω, force needed to move the rod as indicated with a constant speed of  2m/sec is

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a

3.75×10−3N

b

3.75×10−2N

c

3.75×102N

d

3.75×10−4N

answer is A.

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Detailed Solution

Induced current in the circuit  i=BvlRMagnetic force acting on the wire  Fm=Bil=BBvlR l⇒Fm=B2vl2R External force needed to move the rod with constant velocity(Fm)=B2vl2R=(0.15)2×(2)×(0.5)23=3.75×10−3N
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