As shown in the figure, P and Q are two coaxial conducting loops separated by some distance. When the switch S is closed, a clockwise current T_p flows in P (as seen by E) and an induced current ${I_{{Q_1}}}$ flows in Q. The switch remains closed for a long time. When S is opened, a current ${I_{{Q_2}}}$ flows in Q. Then the directions of ${I_{{Q_1}}}$ and ${I_{{Q_2}}}$ (as seen by E) are

Question

As shown in the figure, P and Q are two coaxial conducting loops separated by some distance. When the switch S is closed, a clockwise current T_p flows in P (as seen by E) and an induced current ${I_{{Q_1}}}$ flows in Q. The switch remains closed for a long time. When S is opened, a current ${I_{{Q_2}}}$ flows in Q. Then the directions of ${I_{{Q_1}}}$ and ${I_{{Q_2}}}$ (as seen by E) are

Infinity Learn · Accepted Answer

When switch S is closed magnetic field lines passing through Q increases in the direction from right to left. So, according to Lenz’s law induced current in Q i.e.   will flow in such a direction so that the magnetic field lines due to  passes from left to right through Q. This is possible when   flows in anticlockwise direction as seen by E. Opposite is the case when switch S is opened i.e.  will be clockwise as seen by E

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