As shown in the figure, P and Q are two coaxial conducting loops separated by some distance. When the switch S is closed, a clockwise current I_P flows in P (as seen by E) and an induced current l_Q1 flows in Q. The switch remains closed for a long time. When S is opened, a current I_Q2 flows in Q. Then the directions of I_Q1 and I_Q2 (as seen by E) are

detailed solution

Correct option is D

When switch S is closed magnetic field lines passing through Q increases in the direction from right to left. So, according to Lenz's law induced current in Q i.e. IQ1 will flowin such a direction so that the magnetic field lines due to IQ1 passes from left to right through Q. This is possible when IQ1 flows in anticlockwise direction as seen by E. Opposite is the case when switch S is opened i.e. IQ2 will be clockwise as seen by E