Q.

As shown in the figure, P and Q are two coaxial conducting loops separated by some distance. When the switch S is closed, a clockwise current IP flows in P (as seen by E) and an induced current lQ1 flows in Q. The switch remains closed for a long time. When S is opened, a current IQ2 flows in Q. Then the directions of IQ1 and IQ2 (as seen by E) are

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

respectively clockwise and anticlockwise

b

both clockwise

c

both anticlockwise

d

respectively anticlockwise and clockwise

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

When switch S is closed magnetic field lines passing through Q increases in the direction from right to left. So, according to Lenz's law induced current in Q i.e. IQ1 will flowin such a direction so that the magnetic field lines due to IQ1 passes from left to right through Q. This is possible when IQ1 flows in anticlockwise direction as seen by E. Opposite is the case when switch S is opened i.e. IQ2 will be clockwise as seen by E
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon