As shown in the figure, P and Q are two coaxial conducting loops separated by some distance. When the switch S is closed, a clockwise current $I_{P}$ flows in P (as seen by E) and an induced current $I_{Q 1}$ flows in Q. The switch remains closed for a long time. When S is opened, a current $I_{Q 2}$ flows in Q. Then the directions of $I_{Q 1}$ and $I_{Q 2}$ (as seen by E) are

Question

Infinity Learn · Accepted Answer

When switch S is closed magnetic field lines passing through Q increases in the direction from right to left. So, according to Lenz’s law induced current in Q i.e.$$IQ1will$$ flow in such a direction so that the magnetic field lines due to $$IQ1passes$$ from left to right through Q. This is possible when  $$IQ1flows$$ in anticlockwise direction as seen by E. Opposite is the case when switch S is opened i.e.$$IQ2will$$ be clockwise as seen by E

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