First slide

Rotational motion

Question

Shown in the figure is rigid and uniform one meter long rod AB held in horizontal position by two strings tied to its ends and attached to the ceiling. The rod is of mass ‘m’ and has another weight of mass 2m hung at a distance of 75cm from A. The tension in the string at A is

Easy

A

2mg
B

1mg
C

0.5 mg
D

0.75mg

Solution

Rotational equilibrium.
Taking torque about point B =0
$T_{A} (100) = m g (50) + 2 m g (25) \Rightarrow T_{A} = m g$

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