Shown in the figure is a semicircular metallic strip that has thickness t and resistivity ρ . Its inner radius is $$R1$$ and outer radius is $$R2$$. If a voltage $$V0$$ is applied between its two ends, a current I flows in it. In addition, it is observed that a transverse voltage ΔV develops between its inner and outer surfaces due to purely kinetic effects of moving electrons (ignore$$ any role of the magnetic field due to the $$current). Then $$(figure$$ is schematic and not drawn to $$scale)-$$

Question

Shown in the figure is a semicircular metallic strip that has thickness t and resistivity ρ . Its inner radius is $$R1$$ and outer radius is $$R2$$. If a voltage $$V0$$ is applied between its two ends, a current I flows in it. In addition, it is observed that a transverse voltage ΔV develops between its inner and outer surfaces due to purely kinetic effects of moving electrons (ignore$$ any role of the magnetic field due to the $$current). Then $$(figure$$ is schematic and not drawn to $$scale)-$$

Infinity Learn · Accepted Answer

All the elements are in $$parallell=$$πx and $$A=tdx$$⇒$$dx=$$ρπxtdx∴∫$$1dr=$$∫$$R1R2$$ tdxρπ$$x1r=t$$πρln⁡$$R2R1$$ Resistance $$=$$πρtℓ$$nR2R1i=V0tln$$⁡$$R2R1$$πρ      (A)($$−eE→$$) will be inward direction in order to provide centripetal acceleration. Therefore electric field will be radially outwardVouter

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