Questions
As shown in figure, smaller block m and larger block M move together under the influence of a horizontal force P. The larger block M moves on a frictionless horizontal surface. If coefficient of static friction between the blocks M and m is 0.5. Find minimum value of P. For which the smaller block will not move relative to the larger block.
Given m=1 kg, m=5 kg and
detailed solution
Correct option is A
For Pmin, accelaration a=Pmin(5+1)=Pmin6m/s2Now fmax=μN=mg⇒ N = 1×100.5 = 20N N = ma = 20 ⇒ 20 = 1×Pmin6 ⇒ Pmin = 120NTalk to our academic expert!
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