Shown plane mirror is lying in y-z plane. A particle P has velocity u→=5i^+6j^ at t = 0 and acceleration, a→=2tj^.Velocity of its image at t = 2 s relative to it is

a→=2tj^ dvdt=2tj^ ∫uvdv=∫022tdtj^ v→-u→=2t22j^=t2j^=4j^ v→=5i^+6j^+4j^=5i^+10j^νI=2νM−ν0=2×0−(5i^+(6+2t)j^)At t = 2 sec, νI=5i^+10j^;νI0=νI−ν0Hence, νI0=−5i^+10j^−(5i+10j^)=−10i^