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A silicon specimen is made into a P-type semi-conductor by doping, on an average, one indium atom per $5 \times 10^{7}$ silicon atoms. If the number density of atoms in the silicon specimen is $5 \times 10^{28}$ atoms $m^{- 3},$ then the number of acceptor atoms in silicon per cubic centimetre will be

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2.5×1030 atoms cm−3

1.0×1013 atoms cm−3

1.0×1015 atoms cm−3

2.5×1036 atoms cm−3

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detailed solution

Correct option is C

No of acceptor atoms doped per cubic meter= 5×10285×107= 1021No of acceptor atoms per cubic cm= 1021106=1015

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A silicon specimen is made into a P-type semi-conductor by doping, on an average, one indium atom per 5×107 silicon atoms. If the number density of atoms in the silicon specimen is 5×1028atoms m−3, then the number of acceptor atoms in silicon per cubic centimetre will be

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